Optimal. Leaf size=151 \[ \frac{7 b^{5/2} e \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{9/2}}-\frac{7 b^2 e}{\sqrt{d+e x} (b d-a e)^4}-\frac{7 b e}{3 (d+e x)^{3/2} (b d-a e)^3}-\frac{1}{(a+b x) (d+e x)^{5/2} (b d-a e)}-\frac{7 e}{5 (d+e x)^{5/2} (b d-a e)^2} \]
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Rubi [A] time = 0.306437, antiderivative size = 151, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.179 \[ \frac{7 b^{5/2} e \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{9/2}}-\frac{7 b^2 e}{\sqrt{d+e x} (b d-a e)^4}-\frac{7 b e}{3 (d+e x)^{3/2} (b d-a e)^3}-\frac{1}{(a+b x) (d+e x)^{5/2} (b d-a e)}-\frac{7 e}{5 (d+e x)^{5/2} (b d-a e)^2} \]
Antiderivative was successfully verified.
[In] Int[1/((d + e*x)^(7/2)*(a^2 + 2*a*b*x + b^2*x^2)),x]
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Rubi in Sympy [A] time = 64.2469, size = 134, normalized size = 0.89 \[ - \frac{7 b^{\frac{5}{2}} e \operatorname{atan}{\left (\frac{\sqrt{b} \sqrt{d + e x}}{\sqrt{a e - b d}} \right )}}{\left (a e - b d\right )^{\frac{9}{2}}} - \frac{7 b^{2} e}{\sqrt{d + e x} \left (a e - b d\right )^{4}} + \frac{7 b e}{3 \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )^{3}} - \frac{7 e}{5 \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )^{2}} + \frac{1}{\left (a + b x\right ) \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/(e*x+d)**(7/2)/(b**2*x**2+2*a*b*x+a**2),x)
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Mathematica [A] time = 0.542932, size = 137, normalized size = 0.91 \[ \frac{7 b^{5/2} e \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{9/2}}-\frac{\sqrt{d+e x} \left (\frac{15 b^3}{a+b x}+\frac{20 b e (b d-a e)}{(d+e x)^2}+\frac{6 e (b d-a e)^2}{(d+e x)^3}+\frac{90 b^2 e}{d+e x}\right )}{15 (b d-a e)^4} \]
Antiderivative was successfully verified.
[In] Integrate[1/((d + e*x)^(7/2)*(a^2 + 2*a*b*x + b^2*x^2)),x]
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Maple [A] time = 0.028, size = 149, normalized size = 1. \[ -{\frac{2\,e}{5\, \left ( ae-bd \right ) ^{2}} \left ( ex+d \right ) ^{-{\frac{5}{2}}}}-6\,{\frac{{b}^{2}e}{ \left ( ae-bd \right ) ^{4}\sqrt{ex+d}}}+{\frac{4\,be}{3\, \left ( ae-bd \right ) ^{3}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}-{\frac{{b}^{3}e}{ \left ( ae-bd \right ) ^{4} \left ( bex+ae \right ) }\sqrt{ex+d}}-7\,{\frac{{b}^{3}e}{ \left ( ae-bd \right ) ^{4}\sqrt{b \left ( ae-bd \right ) }}\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{b \left ( ae-bd \right ) }}} \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/(e*x+d)^(7/2)/(b^2*x^2+2*a*b*x+a^2),x)
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b^2*x^2 + 2*a*b*x + a^2)*(e*x + d)^(7/2)),x, algorithm="maxima")
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Fricas [A] time = 0.230973, size = 1, normalized size = 0.01 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b^2*x^2 + 2*a*b*x + a^2)*(e*x + d)^(7/2)),x, algorithm="fricas")
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{\left (a + b x\right )^{2} \left (d + e x\right )^{\frac{7}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/(e*x+d)**(7/2)/(b**2*x**2+2*a*b*x+a**2),x)
[Out]
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GIAC/XCAS [A] time = 0.21342, size = 410, normalized size = 2.72 \[ -\frac{7 \, b^{3} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right ) e}{{\left (b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}\right )} \sqrt{-b^{2} d + a b e}} - \frac{\sqrt{x e + d} b^{3} e}{{\left (b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}\right )}{\left ({\left (x e + d\right )} b - b d + a e\right )}} - \frac{2 \,{\left (45 \,{\left (x e + d\right )}^{2} b^{2} e + 10 \,{\left (x e + d\right )} b^{2} d e + 3 \, b^{2} d^{2} e - 10 \,{\left (x e + d\right )} a b e^{2} - 6 \, a b d e^{2} + 3 \, a^{2} e^{3}\right )}}{15 \,{\left (b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}\right )}{\left (x e + d\right )}^{\frac{5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b^2*x^2 + 2*a*b*x + a^2)*(e*x + d)^(7/2)),x, algorithm="giac")
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